第04章作业(刘)06

求指定截面上的内力。,0yF解：,0BMlMReA[题4-1b]l/2AMeBCl/2RARBlMReB[A+截面]ARFSlMeeMM[C截面]ARFSlMe2lRMMAe2eM[B－截面]ARFSlMelRMMAe0求指定截面上的内力。[题4-1d]Bl/2ql/2CA[A+截面]2SqlF832qlM[C－截面][B－截面]0SF0M2SqlF82qlM[C+截面]2SqlF82qlM[例10]F=qaqB2aaMe=qa2CFAFBDAa2325qaFqaFBAFSxqaMx–+––+289qa23qa23qa2qa2qa23a试作图示刚架的弯矩图。[例16]CBqaaAqaDFAyFAxFB2qaFFFAyAxBBA22qa22qa82qa试作图示刚架的弯矩图。[例16]CBqaaAqaDFAyFAxFB2qaFFFAyAxBBA22qa22qa82qaBAFS