滚筒药柜传动部分运动不干涉分析与仿真-王磊

:1004-2539(2013)03-0097-04(,100192)为了提高滚筒药柜设计的可靠性,降低生产成本,对其工作原理传动结构进行了简要介绍,并详细分析了相邻两个储药斗运动的各个阶段,并确立了各个阶段运动不干涉的条件为了保证储药斗在运动过程中时刻保持水平状态,对药柜两侧平衡杆导轨进行了合理布局设计,以保证储药斗保持水平运行利用Pro/E和RecurDyn建立运动仿真模型,进行储药斗运动仿真,验证运动不干涉分析结果的正确性目前系统已经开发完成,应用于医院门诊药房,运行效果良好滚筒药柜运动不干涉条件运动仿真InterferenceAnalysisandMotionSimulationofErectedCircularMedicine-ChestWangLeiZhangZhiqiangZhangHuaicun(SchoolofMechanical&ElectricalEngineering,BeijingInformationScience&TechnologyUniversity,Beijing100192,China)AbstractIntheerectedcircularmedicine-chest,mechanicalstructureandworkingprincipleareanalyzed,noninterferencemovingconditionofreservingmedicinebasketisdiscussedwithdifferentphase,optimumfunctionofchaindrivebasedonnoninterferencemovingconditionisascertainedandsolvedbyusingMatlab,theminimumcircu-larradiusofreservingmedicinebasketanddesignparametersofchaindrivearefinallyobtained.Forkeepingreservingmedicinebaskethorizontallyrunning,guidesofbalancebararerationallylocated.ThemotionsimulationmodelissetupwithusingPRO/EandRecurDyn.Motionsimulationiscarriedouttoprovethesuccessofoptimumdesignbasedonthenoninterferencemovingconditionofreservingmedicinebasket.Thewholesystemdevelopmenthasbeencompletedandappliedintheoutpatient-servicepharmacy.Itrunswellnow.KeywordsErectedcircularmedicine-chestNoninterferencemovingconditionMotionsimulation0,,,,,,[1-2],,,,,,,,1,HIS,,,[3]21pA,m,973703nk,[4-5]r,c,wh,H,A,sO,,2,O1O2O3O4121234,(x1,y1)(x2,y2)(x3,y3)(x4,y4)A1112,A2234A1A2(X1,Y1)(X2,Y2),1,B,BOO1,O1O2O3O4,O1r,O2O3O4,O2O,O1O2rH0O1O2OO1OO2,H1B,H2O2O3OO2OO312,A1A2$X$Y,0[$X[w,|$Y|h(1)$Xw,[6]2,A1A2O,BH1,(1)822.110[H1[H0,O1r,1A1,O2O3O42A2O1OMatlab,X1Y1$X1=X2-X1$Y1=Y2-Y1=Y1-rsinH1+1.5mp+np(1)0[$X1[wY1-rsinH1+1.5mp+np\h(2)2.22H0H1[H0+H2,O1O2r,1A1R,O3O42A2O3O(1)0[r-Rcos(H1-H0/2)[wRcos(H1-H0/2)-rsinH1+1.5mp+nph(3)2.33H0+H2H1[P,O1O2r,1A1R,O1OO3r,O4,2A2Matlab,X2Y2$X3=X2-X1$Y3=Y1-Y2(3)0[$X3[w$Y3h(4)2.44PH1[H0+(H2+P)/2,O1,O2r,1A1O3,O4,A1A2,9820132A2,A1A2Matlab,X1Y1X2Y2$X4=X2-X1$Y4=Y1-Y2(1)0[$X4[w$Y4h(5)2.55PH1[2H0+H2,O1,O2r,1A1O3r,O4,O4O,2A2,A2A1Matlab,X1Y1X2Y2$X5=X2-X1$Y5=Y2-Y1(1)0[$X5[w$Y5h(6)2.662H0+H2H1[P+H0,O1,O2O2O,1A1O3O4r,2A2R,,(4)2.77P+H0H1[P+H0+H2,O1O2,O3O4,12,,(5)2.88P+H0+H2H1[P+2H0+H2,O1O2O3,O4rO4O,1A12A2,,(6)3,,A1A2[7]30b,X=X1+lsin(P/6)Y=Y1-lcos(P/6)(7),l)))X1)))xY1)))yX)))xY)))y,3,12,1230b,,3423,4,,,,12,:,,4;,,,4,993703,,,30b-30b,556,,,,6,-30b30b,4,,,,4Pro/ERecurDyn,:p=12.7mmw=420mmA=30mms=87mm12Pro/ERecur-Dyn,,CAD,,,,,RecurDyn,,,,RecurDyn,RecurDyn,RecurDyn,[8],,,7,,10s,1000,,11000,8,,5,,,,,,[1].:[J].,2008(5):3-5.[2],,,.[J].,2006,17(19):1469.[3],,,.[J].,2005,21(5):1-4.[4].[M].:,1992:25-32.[5].SolidWorks[D].:,2005:12-18.[6].[J].,2005,32(3):22-23.[7].CAE[D].:,2007:33-37.[8],,.RecurDyn[M].:,2010:320-372.:20120822:20120904:(1986-),,,1002013